極限

\[\lim_{\alpha\rightarrow-1}\frac{z^{\alpha+1}}{\alpha+1}=\Log\left(z\right)+\lim_{\alpha\rightarrow-1}\frac{1}{\alpha+1}\]

\[\lim_{h\rightarrow0}\left(1-h\right)^{\frac{1}{h}}=\frac{1}{e}\]

\[\lim_{x\rightarrow0}x^{\left|a\right|}=\delta_{0a}\]