三角関数と双曲線関数の積分
三角関数の積分
(1)
\[ \int f(\sin x)\cos xdx=\int f(t)dt\cmt{t=\sin x} \](2)
\[ \int f(\cos x)\sin xdx=-\int f(t)dt\cmt{t=\cos x} \](3)
\[ \int f(\tan x)\frac{1}{\cos^{2}x}dx=\int f(t)dt\cmt{t=\tan x} \](4)ワイエルシュトラス置換
\[ \int f(\cos x,\sin x)dx=\int f\left(\frac{1-t^{2}}{1+t^{2}},\frac{2t}{1+t^{2}}\right)\frac{2}{1+t^{2}}dt\cmt{t=\tan\frac{x}{2}} \](1)
\begin{align*} \int f(\sin x)\cos xdx & =\int f(\sin x)d\left(\sin x\right)\\ & =\int f(t)dt\cmt{t=\sin x} \end{align*}(2)
\begin{align*} \int f(\cos x)\sin xdx & =-\int f(\cos x)d\left(\cos x\right)\\ & =-\int f(t)dt\cmt{t=\cos x} \end{align*}(3)
\begin{align*} \int f(\tan x)\frac{1}{\cos^{2}x}dx & =\int f(\tan x)d\left(\tan x\right)\\ & =\int f(t)dt\cmt{t=\tan x} \end{align*}(4)
\begin{align*} \int f(\cos x,\sin x)dx & =\int f\left(\cos^{2}\left(\frac{x}{2}\right)-\sin^{2}\left(\frac{x}{2}\right),2\sin\frac{x}{2}\cos\frac{x}{2}\right)dx\\ & =\int f\left(\frac{1-\tan^{2}\frac{x}{2}}{1+\tan^{2}\frac{x}{2}},\frac{2\tan\frac{x}{2}}{1+\tan^{2}\frac{x}{2}}\right)dx\\ & =\int f\left(\frac{1-t^{2}}{1+t^{2}},\frac{2t}{1+t^{2}}\right)d\left(2\tan^{\bullet}t\right)\cmt{t=\tan\frac{x}{2}}\\ & =\int f\left(\frac{1-t^{2}}{1+t^{2}},\frac{2t}{1+t^{2}}\right)\frac{2}{1+t^{2}}dt \end{align*}双曲線関数の積分
(1)
\[ \int f(\sinh x)\cosh xdx=\int f(t)dt\cmt{t=\sinh x} \](2)
\[ \int f(\cosh x)\sinh xdx=\int f(t)dt\cmt{t=\cosh x} \](3)
\[ \int f(\tanh x)\frac{1}{\cosh^{2}x}dx=\int f(t)dt\cmt{t=\tanh x} \](4)
\[ \int f(\cosh x,\sinh x)dx=\int f\left(\frac{1+t^{2}}{1-t^{2}},\frac{2t}{1-t^{2}}\right)\frac{2}{1-t^{2}}dt\cmt{t=\tanh\frac{x}{2}} \](1)
\begin{align*} \int f(\sinh x)\cosh xdx & =\int f(\sinh x)d\left(\sinh x\right)\\ & =\int f(t)dt\cmt{t=\sinh x} \end{align*}(2)
\begin{align*} \int f(\cosh)\sinh xdx & =\int f(\cosh x)d\left(\cosh x\right)\\ & =\int f(t)dt\cmt{t=\cosh x} \end{align*}(3)
\begin{align*} \int f(\tanh x)\frac{1}{\cosh^{2}x}dx & =\int f(\tanh x)d\left(\tanh x\right)\\ & =\int f(t)dt\cmt{t=\tanh x} \end{align*}(4)
\begin{align*} \int f(\cosh x,\sinh x)dx & =\int f\left(\cosh^{2}\left(\frac{x}{2}\right)+\sinh^{2}\left(\frac{x}{2}\right),2\sinh\frac{x}{2}\cosh\frac{x}{2}\right)dx\\ & =\int f\left(\frac{1+\tanh^{2}\frac{x}{2}}{1-\tanh^{2}\frac{x}{2}},\frac{2\tanh\frac{x}{2}}{1-\tanh^{2}\frac{x}{2}}\right)dx\\ & =\int f\left(\frac{1+t^{2}}{1-t^{2}},\frac{2t}{1-t^{2}}\right)d\left(2\tanh^{\bullet}t\right)\cmt{t=\tanh\frac{x}{2}}\\ & =\int f\left(\frac{1+t^{2}}{1-t^{2}},\frac{2t}{1-t^{2}}\right)\frac{2}{1-t^{2}}dt \end{align*}ページ情報
タイトル | 三角関数と双曲線関数の積分 |
URL | https://www.nomuramath.com/gevgau89/ |
SNSボタン |
3角関数・双曲線関数の無限乗積展開
\[
\sin\left(\pi z\right)=\pi z\prod_{k=1}^{\infty}\left(1-\frac{z^{2}}{k^{2}}\right)
\]
三角関数と双曲線関数の対数の積分
\[
\int\Log\sin^{\alpha}zdz=z\Log\sin^{\alpha}x+\frac{i\alpha}{2}z^{2}+\alpha z\Li_{1}\left(e^{2iz}\right)+\frac{i\alpha}{2}\Li_{2}\left(e^{2iz}\right)+\C{}
\]
三角関数と双曲線関数の冪乗積分漸化式
\[
\int\sin^{n}xdx=-\frac{1}{n}\cos x\sin^{n-1}x+\frac{n-1}{n}\int\sin^{n-2}xdx\qquad(n\ne0)
\]
三角関数・双曲線関数の一次結合の逆数の積分
\[
\int\frac{1}{\alpha\sin z+\beta\cos z+\gamma}dz=-\frac{2}{\sqrt{\alpha^{2}+\beta^{2}-\gamma^{2}}}\tanh^{\bullet}\frac{\left(\gamma-\beta\right)\tan\frac{z}{2}+\alpha}{\sqrt{\alpha^{2}+\beta^{2}-\gamma^{2}}}+C
\]